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1/5h-9=15
We move all terms to the left:
1/5h-9-(15)=0
Domain of the equation: 5h!=0We add all the numbers together, and all the variables
h!=0/5
h!=0
h∈R
1/5h-24=0
We multiply all the terms by the denominator
-24*5h+1=0
Wy multiply elements
-120h+1=0
We move all terms containing h to the left, all other terms to the right
-120h=-1
h=-1/-120
h=1/120
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