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1/5h=17
We move all terms to the left:
1/5h-(17)=0
Domain of the equation: 5h!=0We multiply all the terms by the denominator
h!=0/5
h!=0
h∈R
-17*5h+1=0
Wy multiply elements
-85h+1=0
We move all terms containing h to the left, all other terms to the right
-85h=-1
h=-1/-85
h=1/85
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