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1/5hh=10
We move all terms to the left:
1/5hh-(10)=0
Domain of the equation: 5hh!=0We multiply all the terms by the denominator
h!=0/1
h!=0
h∈R
-10*5hh+1=0
Wy multiply elements
-50h+1=0
We move all terms containing h to the left, all other terms to the right
-50h=-1
h=-1/-50
h=1/50
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