1/5k-(k+1/2)=1/10(k+2)

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Solution for 1/5k-(k+1/2)=1/10(k+2) equation: 


k in (-oo:+oo)

(1/5)*k-k-(1/2) = (1/10)*(k+2) // - (1/10)*(k+2)

(1/5)*k-((1/10)*(k+2))-k-(1/2) = 0

(-1/10)*(k+2)+(1/5)*k-k-1/2 = 0

k/5-1/10*(k+2)-k-1/2 = 0

(-1/10*2*5*(k+2))/(2*5)+(2*k)/(2*5)+(2*5*(-k))/(2*5)+(-1*5)/(2*5) = 0

2*k-1/10*2*5*(k+2)+2*5*(-k)-1*5 = 0

k-10*k-5-2 = 0

-9*k-5-2 = 0

-9*k-7 = 0

(-9*k-7)/(2*5) = 0

(-9*k-7)/(2*5) = 0 // * 2*5

-9*k-7 = 0

-9*k-7 = 0 // + 7

-9*k = 7 // : -9

k = 7/(-9)

k = -7/9

k = -7/9

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