1/5k-(k+1/5)=(k+1)

Solution for 1/5k-(k+1/5)=(k+1) equation:

1/5k-(k+1/5)=(k+1)

We move all terms to the left:

1/5k-(k+1/5)-((k+1))=0


Domain of the equation: 5k!=0

k!=0/5

k!=0

k∈R


We add all the numbers together, and all the variables

1/5k-(+k+1/5)-((k+1))=0

We get rid of parentheses

1/5k-k-((k+1))-1/5=0

We calculate fractions


-k-((k+1))=0


We calculate terms in parentheses: -((k+1)), so:

(k+1)

We get rid of parentheses

k+1

Back to the equation:

-(k+1)


We add all the numbers together, and all the variables

-1k-(k+1)=0

We get rid of parentheses

-1k-k-1=0

We add all the numbers together, and all the variables

-2k-1=0

We move all terms containing k to the left, all other terms to the right

-2k=1

k=1/-2

k=-1/2