1/5ln(300x)=2

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Solution for 1/5ln(300x)=2 equation: 


D( x )

300*x <= 0

300*x <= 0

300*x <= 0

300*x+0 <= 0 // - 0

300*x <= 0 // : 300

x <= 0/300

x <= 0

x in (0:+oo)

(1/5)*ln(300*x) = 2 // - 2

(1/5)*ln(300*x)-2 = 0

1/5*ln(300*x)-2 = 0 // + 2

1/5*ln(300*x) = 2 // : 1/5

ln(300*x) = 2/1/5

ln(300*x) = 10

ln(300*x) = ln(e^10)

300*x = e^10

300*x-e^10 = 0 // + e^10

300*x = e^10 // : 300

x = (e^10)/300

x = (e^10)/300

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