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1/5n+3=1/2n
We move all terms to the left:
1/5n+3-(1/2n)=0
Domain of the equation: 5n!=0
n!=0/5
n!=0
n∈R
Domain of the equation: 2n)!=0We add all the numbers together, and all the variables
n!=0/1
n!=0
n∈R
1/5n-(+1/2n)+3=0
We get rid of parentheses
1/5n-1/2n+3=0
We calculate fractions
2n/10n^2+(-5n)/10n^2+3=0
We multiply all the terms by the denominator
2n+(-5n)+3*10n^2=0
Wy multiply elements
30n^2+2n+(-5n)=0
We get rid of parentheses
30n^2+2n-5n=0
We add all the numbers together, and all the variables
30n^2-3n=0
a = 30; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·30·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*30}=\frac{0}{60} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*30}=\frac{6}{60} =1/10 $
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