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1/5n+5=n
We move all terms to the left:
1/5n+5-(n)=0
Domain of the equation: 5n!=0We add all the numbers together, and all the variables
n!=0/5
n!=0
n∈R
-1n+1/5n+5=0
We multiply all the terms by the denominator
-1n*5n+5*5n+1=0
Wy multiply elements
-5n^2+25n+1=0
a = -5; b = 25; c = +1;
Δ = b2-4ac
Δ = 252-4·(-5)·1
Δ = 645
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{645}}{2*-5}=\frac{-25-\sqrt{645}}{-10} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{645}}{2*-5}=\frac{-25+\sqrt{645}}{-10} $
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