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1/5p+9/p+6=30
We move all terms to the left:
1/5p+9/p+6-(30)=0
Domain of the equation: 5p!=0
p!=0/5
p!=0
p∈R
Domain of the equation: p!=0We add all the numbers together, and all the variables
p∈R
1/5p+9/p-24=0
We calculate fractions
p/5p^2+45p/5p^2-24=0
We multiply all the terms by the denominator
p+45p-24*5p^2=0
We add all the numbers together, and all the variables
46p-24*5p^2=0
Wy multiply elements
-120p^2+46p=0
a = -120; b = 46; c = 0;
Δ = b2-4ac
Δ = 462-4·(-120)·0
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-46}{2*-120}=\frac{-92}{-240} =23/60 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+46}{2*-120}=\frac{0}{-240} =0 $
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