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1/5p=3
We move all terms to the left:
1/5p-(3)=0
Domain of the equation: 5p!=0We multiply all the terms by the denominator
p!=0/5
p!=0
p∈R
-3*5p+1=0
Wy multiply elements
-15p+1=0
We move all terms containing p to the left, all other terms to the right
-15p=-1
p=-1/-15
p=1/15
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