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1/5s+s=12
We move all terms to the left:
1/5s+s-(12)=0
Domain of the equation: 5s!=0We add all the numbers together, and all the variables
s!=0/5
s!=0
s∈R
s+1/5s-12=0
We multiply all the terms by the denominator
s*5s-12*5s+1=0
Wy multiply elements
5s^2-60s+1=0
a = 5; b = -60; c = +1;
Δ = b2-4ac
Δ = -602-4·5·1
Δ = 3580
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3580}=\sqrt{4*895}=\sqrt{4}*\sqrt{895}=2\sqrt{895}$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-2\sqrt{895}}{2*5}=\frac{60-2\sqrt{895}}{10} $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+2\sqrt{895}}{2*5}=\frac{60+2\sqrt{895}}{10} $
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