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1/5t=7
We move all terms to the left:
1/5t-(7)=0
Domain of the equation: 5t!=0We multiply all the terms by the denominator
t!=0/5
t!=0
t∈R
-7*5t+1=0
Wy multiply elements
-35t+1=0
We move all terms containing t to the left, all other terms to the right
-35t=-1
t=-1/-35
t=1/35
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