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1/5x+-2.2x=-5.34+1.54
We move all terms to the left:
1/5x+-2.2x-(-5.34+1.54)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
1/5x-2.2x+-(-3.8)=0
We add all the numbers together, and all the variables
-2.2x+1/5x+3.8=0
We multiply all the terms by the denominator
-(2.2x)*5x+(3.8)*5x+1=0
We add all the numbers together, and all the variables
-(+2.2x)*5x+(3.8)*5x+1=0
We multiply parentheses
-10x^2+19x+1=0
a = -10; b = 19; c = +1;
Δ = b2-4ac
Δ = 192-4·(-10)·1
Δ = 401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{401}}{2*-10}=\frac{-19-\sqrt{401}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{401}}{2*-10}=\frac{-19+\sqrt{401}}{-20} $
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