1/5x+0.3x=1/2x

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Solution for 1/5x+0.3x=1/2x equation:



1/5x+0.3x=1/2x
We move all terms to the left:
1/5x+0.3x-(1/2x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 2x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
1/5x+0.3x-(+1/2x)=0
We add all the numbers together, and all the variables
0.3x+1/5x-(+1/2x)=0
We get rid of parentheses
0.3x+1/5x-1/2x=0
We calculate fractions
0.3x+2x/10x^2+(-5x)/10x^2=0
We multiply all the terms by the denominator
(0.3x)*10x^2+2x+(-5x)=0
We add all the numbers together, and all the variables
(+0.3x)*10x^2+2x+(-5x)=0
We add all the numbers together, and all the variables
2x+(+0.3x)*10x^2+(-5x)=0
We get rid of parentheses
2x+(+0.3x)*10x^2-5x=0
We add all the numbers together, and all the variables
-3x+(+0.3x)*10x^2=0

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