1/5x+1/2y=2;1/5x+3y=17

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Solution for 1/5x+1/2y=2;1/5x+3y=17 system of equations: 


  • /| (1/5)*x+(1/2)*y-2 = 0| (1/5)*x+3*y-17 = 0
  • We try to solve the equation: (1/5)*x+(1/2)*y-2 = 0
  • 1/5*x+1/2*y-2 = 0 // - 1/5*x-2
  • 1/2*y = -(1/5*x-2) // : 1/2
  • y = (-(1/5*x-2))/1/2
  • y = 2*(2-(1/5*x))
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 2*3*(2-(1/5*x))+(1/5)*x-17 = 0| y = 2*(2-(1/5*x))
  • 6*(2-1/5*x)+x/5-17 = 0
  • 12-x-17 = 0
  • -x-5 = 0
  • -x-5 = 0 // + 5
  • -x = 5 // * -1
  • x = -5
  • We insert the solution into one of the initial equations of our system of equations
  • For y = 2*(2-(1/5*x)): 
  • y = 2*(2-(-5*1/5))
  • y = 2*(1+2)
  • y = 2*3
  • y = 6
  • We get a system of equations:
  • /| y = 6| x = -5

 

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