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1/5x+1/3=-2(3/4x+2)
We move all terms to the left:
1/5x+1/3-(-2(3/4x+2))=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 4x+2))!=0We calculate fractions
x∈R
(-(-2(3*5x*3)/20x^2+80x^2/20x^2+4x/20x^2=0
We can not solve this equation
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