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1/5x+1/3x=2/5
We move all terms to the left:
1/5x+1/3x-(2/5)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
1/5x+1/3x-(+2/5)=0
We get rid of parentheses
1/5x+1/3x-2/5=0
We calculate fractions
3x/375x^2+125x/375x^2+(-6x)/375x^2=0
We multiply all the terms by the denominator
3x+125x+(-6x)=0
We add all the numbers together, and all the variables
128x+(-6x)=0
We get rid of parentheses
128x-6x=0
We add all the numbers together, and all the variables
122x=0
x=0/122
x=0
Równanie nie ma rozwiązania
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