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1/5x+1/4=-3(4/5x+3)
We move all terms to the left:
1/5x+1/4-(-3(4/5x+3))=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 5x+3))!=0We calculate fractions
x∈R
(-(-3(4*5x*4)/25x^2+125x^2/25x^2+5x/25x^2=0
We can not solve this equation
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