1/5x+1/4x=1350

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Solution for 1/5x+1/4x=1350 equation:



1/5x+1/4x=1350
We move all terms to the left:
1/5x+1/4x-(1350)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
We calculate fractions
4x/20x^2+5x/20x^2-1350=0
We multiply all the terms by the denominator
4x+5x-1350*20x^2=0
We add all the numbers together, and all the variables
9x-1350*20x^2=0
Wy multiply elements
-27000x^2+9x=0
a = -27000; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-27000)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-27000}=\frac{-18}{-54000} =1/3000 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-27000}=\frac{0}{-54000} =0 $

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