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1/5x+1/6(x+2)=15
We move all terms to the left:
1/5x+1/6(x+2)-(15)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 6(x+2)!=0We calculate fractions
x∈R
(6xx/(30x^2x+5x/(30x^2x-15=0
We can not solve this equation
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