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1/5x+1/7=4(5/3x+3)
We move all terms to the left:
1/5x+1/7-(4(5/3x+3))=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3x+3))!=0We calculate fractions
x∈R
(-(4(5*5x*7)/15x^2+45x^2/15x^2+3x/15x^2=0
We can not solve this equation
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