1/5x+10=1/2x+20

Solution for 1/5x+10=1/2x+20 equation:

1/5x+10=1/2x+20

We move all terms to the left:

1/5x+10-(1/2x+20)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 2x+20)!=0

x∈R


We get rid of parentheses

1/5x-1/2x-20+10=0

We calculate fractions


2x/10x^2+(-5x)/10x^2-20+10=0

We add all the numbers together, and all the variables

2x/10x^2+(-5x)/10x^2-10=0

We multiply all the terms by the denominator


2x+(-5x)-10*10x^2=0

Wy multiply elements

-100x^2+2x+(-5x)=0

We get rid of parentheses

-100x^2+2x-5x=0

We add all the numbers together, and all the variables

-100x^2-3x=0

a = -100; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·(-100)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*-100}=\frac{0}{-200}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*-100}=\frac{6}{-200}
=-3/100
$