1/5x+10=3/2x+3

Solution for 1/5x+10=3/2x+3 equation:

1/5x+10=3/2x+3

We move all terms to the left:

1/5x+10-(3/2x+3)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 2x+3)!=0

x∈R


We get rid of parentheses

1/5x-3/2x-3+10=0

We calculate fractions


2x/10x^2+(-15x)/10x^2-3+10=0

We add all the numbers together, and all the variables

2x/10x^2+(-15x)/10x^2+7=0

We multiply all the terms by the denominator


2x+(-15x)+7*10x^2=0

Wy multiply elements

70x^2+2x+(-15x)=0

We get rid of parentheses

70x^2+2x-15x=0

We add all the numbers together, and all the variables

70x^2-13x=0

a = 70; b = -13; c = 0;
Δ = b2-4ac
Δ = -132-4·70·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-13}{2*70}=\frac{0}{140}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+13}{2*70}=\frac{26}{140}
=13/70
$