1/5x+13+x=-1/10(x+40)+4

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Solution for 1/5x+13+x=-1/10(x+40)+4 equation: 


x in (-oo:+oo)

(1/5)*x+x+13 = (-1/10)*(x+40)+4 // - (-1/10)*(x+40)+4

(1/5)*x-((-1/10)*(x+40))+x-4+13 = 0

(1/10)*(x+40)+(1/5)*x+x-4+13 = 0

1/10*(x+40)+x/5+x-4+13 = 0

(1/10*5*(x+40))/5+x/5+(5*x)/5+(-4*5)/5+(5*13)/5 = 0

1/10*5*(x+40)+x+5*x-4*5+5*13 = 0

3/2*x+5*x-20+20+65 = 0

13/2*x-20+20+65 = 0

13/2*x+65 = 0

(13/2*x+65)/5 = 0

(13/2*x+65)/5 = 0 // * 5

13/2*x+65 = 0

13/2*x+65 = 0 // - 65

13/2*x = -65 // : 13/2

x = -65/13/2

x = -10

x = -10

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