1/5x+13+x=-1/10(x-40)+4

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Solution for 1/5x+13+x=-1/10(x-40)+4 equation: 


x in (-oo:+oo)

(1/5)*x+x+13 = (-1/10)*(x-40)+4 // - (-1/10)*(x-40)+4

(1/5)*x-((-1/10)*(x-40))+x-4+13 = 0

(1/10)*(x-40)+(1/5)*x+x-4+13 = 0

1/10*(x-40)+x/5+x-4+13 = 0

(1/10*5*(x-40))/5+x/5+(5*x)/5+(-4*5)/5+(5*13)/5 = 0

1/10*5*(x-40)+x+5*x-4*5+5*13 = 0

3/2*x+5*x-20-20+65 = 0

13/2*x-20-20+65 = 0

13/2*x-40+65 = 0

13/2*x+25 = 0

(13/2*x+25)/5 = 0

(13/2*x+25)/5 = 0 // * 5

13/2*x+25 = 0

13/2*x+25 = 0 // - 25

13/2*x = -25 // : 13/2

x = -25/13/2

x = -50/13

x = -50/13

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