1/5x+16=4/5x-41

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Solution for 1/5x+16=4/5x-41 equation:



1/5x+16=4/5x-41
We move all terms to the left:
1/5x+16-(4/5x-41)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 5x-41)!=0
x∈R
We get rid of parentheses
1/5x-4/5x+41+16=0
We multiply all the terms by the denominator
41*5x+16*5x+1-4=0
We add all the numbers together, and all the variables
41*5x+16*5x-3=0
Wy multiply elements
205x+80x-3=0
We add all the numbers together, and all the variables
285x-3=0
We move all terms containing x to the left, all other terms to the right
285x=3
x=3/285
x=1/95

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