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1/5x+2+3/5x=10
We move all terms to the left:
1/5x+2+3/5x-(10)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
1/5x+3/5x-8=0
We multiply all the terms by the denominator
-8*5x+1+3=0
We add all the numbers together, and all the variables
-8*5x+4=0
Wy multiply elements
-40x+4=0
We move all terms containing x to the left, all other terms to the right
-40x=-4
x=-4/-40
x=1/10
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