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1/5x+2/5x+180=x
We move all terms to the left:
1/5x+2/5x+180-(x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-1x+1/5x+2/5x+180=0
We multiply all the terms by the denominator
-1x*5x+180*5x+1+2=0
We add all the numbers together, and all the variables
-1x*5x+180*5x+3=0
Wy multiply elements
-5x^2+900x+3=0
a = -5; b = 900; c = +3;
Δ = b2-4ac
Δ = 9002-4·(-5)·3
Δ = 810060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{810060}=\sqrt{4*202515}=\sqrt{4}*\sqrt{202515}=2\sqrt{202515}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(900)-2\sqrt{202515}}{2*-5}=\frac{-900-2\sqrt{202515}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(900)+2\sqrt{202515}}{2*-5}=\frac{-900+2\sqrt{202515}}{-10} $
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