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1/5x+2/x=-4
We move all terms to the left:
1/5x+2/x-(-4)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
1/5x+2/x+4=0
We calculate fractions
x/5x^2+10x/5x^2+4=0
We multiply all the terms by the denominator
x+10x+4*5x^2=0
We add all the numbers together, and all the variables
11x+4*5x^2=0
Wy multiply elements
20x^2+11x=0
a = 20; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·20·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*20}=\frac{-22}{40} =-11/20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*20}=\frac{0}{40} =0 $
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