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1/5x+3=12
We move all terms to the left:
1/5x+3-(12)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
1/5x-9=0
We multiply all the terms by the denominator
-9*5x+1=0
Wy multiply elements
-45x+1=0
We move all terms containing x to the left, all other terms to the right
-45x=-1
x=-1/-45
x=1/45
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