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1/5x+3=16
We move all terms to the left:
1/5x+3-(16)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
1/5x-13=0
We multiply all the terms by the denominator
-13*5x+1=0
Wy multiply elements
-65x+1=0
We move all terms containing x to the left, all other terms to the right
-65x=-1
x=-1/-65
x=1/65
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