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1/5x+5x=65
We move all terms to the left:
1/5x+5x-(65)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
5x+1/5x-65=0
We multiply all the terms by the denominator
5x*5x-65*5x+1=0
Wy multiply elements
25x^2-325x+1=0
a = 25; b = -325; c = +1;
Δ = b2-4ac
Δ = -3252-4·25·1
Δ = 105525
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{105525}=\sqrt{225*469}=\sqrt{225}*\sqrt{469}=15\sqrt{469}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-325)-15\sqrt{469}}{2*25}=\frac{325-15\sqrt{469}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-325)+15\sqrt{469}}{2*25}=\frac{325+15\sqrt{469}}{50} $
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