1/5x+X=20

Solution for 1/5x+X=20 equation:

1/5x+x=20

We move all terms to the left:

1/5x+x-(20)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We add all the numbers together, and all the variables

x+1/5x-20=0

We multiply all the terms by the denominator


x*5x-20*5x+1=0

Wy multiply elements

5x^2-100x+1=0

a = 5; b = -100; c = +1;
Δ = b2-4ac
Δ = -1002-4·5·1
Δ = 9980
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9980}=\sqrt{4*2495}=\sqrt{4}*\sqrt{2495}=2\sqrt{2495}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-2\sqrt{2495}}{2*5}=\frac{100-2\sqrt{2495}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+2\sqrt{2495}}{2*5}=\frac{100+2\sqrt{2495}}{10}
$