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1/5x+x=18
We move all terms to the left:
1/5x+x-(18)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
x+1/5x-18=0
We multiply all the terms by the denominator
x*5x-18*5x+1=0
Wy multiply elements
5x^2-90x+1=0
a = 5; b = -90; c = +1;
Δ = b2-4ac
Δ = -902-4·5·1
Δ = 8080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8080}=\sqrt{16*505}=\sqrt{16}*\sqrt{505}=4\sqrt{505}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-4\sqrt{505}}{2*5}=\frac{90-4\sqrt{505}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+4\sqrt{505}}{2*5}=\frac{90+4\sqrt{505}}{10} $
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