1/5x-0.4=1/10x+0.6

Solution for 1/5x-0.4=1/10x+0.6 equation:

1/5x-0.4=1/10x+0.6

We move all terms to the left:

1/5x-0.4-(1/10x+0.6)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 10x+0.6)!=0

x∈R


We get rid of parentheses

1/5x-1/10x-0.6-0.4=0

We calculate fractions


10x/50x^2+(-5x)/50x^2-0.6-0.4=0

We add all the numbers together, and all the variables

10x/50x^2+(-5x)/50x^2-1=0

We multiply all the terms by the denominator


10x+(-5x)-1*50x^2=0

Wy multiply elements

-50x^2+10x+(-5x)=0

We get rid of parentheses

-50x^2+10x-5x=0

We add all the numbers together, and all the variables

-50x^2+5x=0

a = -50; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-50)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-50}=\frac{-10}{-100}
=1/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-50}=\frac{0}{-100}
=0
$