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1/5x-10=49
We move all terms to the left:
1/5x-10-(49)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
1/5x-59=0
We multiply all the terms by the denominator
-59*5x+1=0
Wy multiply elements
-295x+1=0
We move all terms containing x to the left, all other terms to the right
-295x=-1
x=-1/-295
x=1/295
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