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1/5x-2/5-1/2x=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 2x!=0We calculate fractions
x!=0/2
x!=0
x∈R
2x/250x^2+(-125x)/250x^2+(-4x)/250x^2=0
We multiply all the terms by the denominator
2x+(-125x)+(-4x)=0
We get rid of parentheses
2x-125x-4x=0
We add all the numbers together, and all the variables
-127x=0
x=0/-127
x=0
Równanie nie ma rozwiązania
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