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1/5x-23=x+13
We move all terms to the left:
1/5x-23-(x+13)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
1/5x-x-13-23=0
We multiply all the terms by the denominator
-x*5x-13*5x-23*5x+1=0
Wy multiply elements
-5x^2-65x-115x+1=0
We add all the numbers together, and all the variables
-5x^2-180x+1=0
a = -5; b = -180; c = +1;
Δ = b2-4ac
Δ = -1802-4·(-5)·1
Δ = 32420
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32420}=\sqrt{4*8105}=\sqrt{4}*\sqrt{8105}=2\sqrt{8105}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180)-2\sqrt{8105}}{2*-5}=\frac{180-2\sqrt{8105}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180)+2\sqrt{8105}}{2*-5}=\frac{180+2\sqrt{8105}}{-10} $
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