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1/5x-7=2/10x+6
We move all terms to the left:
1/5x-7-(2/10x+6)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 10x+6)!=0We get rid of parentheses
x∈R
1/5x-2/10x-6-7=0
We calculate fractions
10x/50x^2+(-10x)/50x^2-6-7=0
We add all the numbers together, and all the variables
10x/50x^2+(-10x)/50x^2-13=0
We multiply all the terms by the denominator
10x+(-10x)-13*50x^2=0
Wy multiply elements
-650x^2+10x+(-10x)=0
We get rid of parentheses
-650x^2+10x-10x=0
We add all the numbers together, and all the variables
-650x^2=0
a = -650; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-650)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-1300}=0$
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