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1/5x-8=1/2(x-4)
We move all terms to the left:
1/5x-8-(1/2(x-4))=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 2(x-4))!=0We calculate fractions
x∈R
(2xx/(10x^2x+(-(1*5x)/(10x^2x-8=0
We can not solve this equation
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