1/5x1/10x+3/20x=36

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Solution for 1/5x1/10x+3/20x=36 equation: 


x in (-oo:+oo)

(((1/5)*x^1)/10)*x+(3/20)*x = 36 // - 36

(((1/5)*x^1)/10)*x+(3/20)*x-36 = 0

(((1/5)*x)/10)*x+(3/20)*x-36 = 0

1/50*x^2+3/20*x-36 = 0

DELTA = (3/20)^2-(-36*1/50*4)

DELTA = 1161/400

DELTA > 0

x = ((1161/400)^(1/2)-3/20)/(1/50*2) or x = (-(1161/400)^(1/2)-3/20)/(1/50*2)

x = 25*((1161/400)^(1/2)-3/20) or x = -25*((1161/400)^(1/2)+3/20)

x in { -25*((1161/400)^(1/2)+3/20), 25*((1161/400)^(1/2)-3/20) }

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