1/5x2(20x2-10x+5)

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Solution for 1/5x2(20x2-10x+5) equation: 


x in (-oo:+oo)

(1/5)*x^2*(20*x^2-(10*x)+5) = 0

(1/5)*x^2*(20*x^2-10*x+5) = 0

1/5*x^2*(20*x^2-10*x+5) = 0

20*x^2-10*x+5 = 0

5*(4*x^2-2*x+1) = 0

4*x^2-2*x+1 = 0

DELTA = (-2)^2-(1*4*4)

DELTA = -12

DELTA < 0

5 = 0

1/5*5*x^2 = 0

1/5*x^2 = 0 // : 1/5

x^2 = 0

x = 0

x = 0

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