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1/5x=1/4x-5
We move all terms to the left:
1/5x-(1/4x-5)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 4x-5)!=0We get rid of parentheses
x∈R
1/5x-1/4x+5=0
We calculate fractions
4x/20x^2+(-5x)/20x^2+5=0
We multiply all the terms by the denominator
4x+(-5x)+5*20x^2=0
Wy multiply elements
100x^2+4x+(-5x)=0
We get rid of parentheses
100x^2+4x-5x=0
We add all the numbers together, and all the variables
100x^2-1x=0
a = 100; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·100·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*100}=\frac{0}{200} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*100}=\frac{2}{200} =1/100 $
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