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1/5x=10x
We move all terms to the left:
1/5x-(10x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-10x+1/5x=0
We multiply all the terms by the denominator
-10x*5x+1=0
Wy multiply elements
-50x^2+1=0
a = -50; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-50)·1
Δ = 200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{200}=\sqrt{100*2}=\sqrt{100}*\sqrt{2}=10\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{2}}{2*-50}=\frac{0-10\sqrt{2}}{-100} =-\frac{10\sqrt{2}}{-100} =-\frac{\sqrt{2}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{2}}{2*-50}=\frac{0+10\sqrt{2}}{-100} =\frac{10\sqrt{2}}{-100} =\frac{\sqrt{2}}{-10} $
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