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1/5x=11+(x+3)
We move all terms to the left:
1/5x-(11+(x+3))=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
-((11+(x+3)))*5x+1=0
We move all terms containing x to the left, all other terms to the right
-((11+(x+3)))*5x=-1
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