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1/5y+2=2/5
We move all terms to the left:
1/5y+2-(2/5)=0
Domain of the equation: 5y!=0We add all the numbers together, and all the variables
y!=0/5
y!=0
y∈R
1/5y+2-(+2/5)=0
We get rid of parentheses
1/5y+2-2/5=0
We calculate fractions
2!=0
There is no solution for this equation
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