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1/5y+3=11
We move all terms to the left:
1/5y+3-(11)=0
Domain of the equation: 5y!=0We add all the numbers together, and all the variables
y!=0/5
y!=0
y∈R
1/5y-8=0
We multiply all the terms by the denominator
-8*5y+1=0
Wy multiply elements
-40y+1=0
We move all terms containing y to the left, all other terms to the right
-40y=-1
y=-1/-40
y=1/40
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