1/5y+4y=-3

Solution for 1/5y+4y=-3 equation:

1/5y+4y=-3

We move all terms to the left:

1/5y+4y-(-3)=0


Domain of the equation: 5y!=0

y!=0/5

y!=0

y∈R


We add all the numbers together, and all the variables

4y+1/5y+3=0

We multiply all the terms by the denominator


4y*5y+3*5y+1=0

Wy multiply elements

20y^2+15y+1=0

a = 20; b = 15; c = +1;
Δ = b2-4ac
Δ = 152-4·20·1
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{145}}{2*20}=\frac{-15-\sqrt{145}}{40}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{145}}{2*20}=\frac{-15+\sqrt{145}}{40}
$