1/5z+3+3/5z=27

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Solution for 1/5z+3+3/5z=27 equation:



1/5z+3+3/5z=27
We move all terms to the left:
1/5z+3+3/5z-(27)=0
Domain of the equation: 5z!=0
z!=0/5
z!=0
z∈R
We add all the numbers together, and all the variables
1/5z+3/5z-24=0
We multiply all the terms by the denominator
-24*5z+1+3=0
We add all the numbers together, and all the variables
-24*5z+4=0
Wy multiply elements
-120z+4=0
We move all terms containing z to the left, all other terms to the right
-120z=-4
z=-4/-120
z=1/30

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