1/5z+3=12

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Solution for 1/5z+3=12 equation: 



1/5z+3=12

We move all terms to the left:

1/5z+3-(12)=0



Domain of the equation: 5z!=0

z!=0/5

z!=0

z∈R



We add all the numbers together, and all the variables

1/5z-9=0

We multiply all the terms by the denominator


-9*5z+1=0

Wy multiply elements

-45z+1=0

We move all terms containing z to the left, all other terms to the right

-45z=-1

z=-1/-45

z=1/45

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